SQL INTERVIEW QUESTION | Hotel Booking Management

 DROP TABLE IF EXISTS Bookings;


CREATE TABLE Bookings (

    BookingID INT PRIMARY KEY,

    BookingDate DATE,

    RoomNumber INT

);


-- Sample data

INSERT INTO Bookings VALUES

(1, '2024-01-01', 101),

(2, '2024-01-02', 101),

(3, '2024-01-04', 101),

(4, '2024-01-01', 102),

(5, '2024-01-05', 102);



SELECT * FROM Bookings

Comments

Post a Comment

Popular posts from this blog

50 Essential SQL Questions to Land Your Dream Job

 CREATE TABLE worker (     first_name VARCHAR(50),     last_name VARCHAR(50),     department VARCHAR(50),     salary DECIMAL(10, 2),     joining_date DATE ); INSERT INTO worker (first_name, last_name, department, salary, joining_date) VALUES  ('John', 'Doe', 'HR', 55000, '2020-01-15'), ('Jane', 'Smith', 'Finance', 67000, '2019-03-22'), ('Robert', 'Johnson', 'IT', 72000, '2018-06-10'), ('Emily', 'Davis', 'Marketing', 59000, '2021-07-01'), ('Michael', 'Wilson', 'Sales', 63000, '2020-09-15'), ('Sarah', 'Brown', 'HR', 56000, '2022-02-19'), ('David', 'Miller', 'Finance', 68000, '2019-10-05'), ('Laura', 'Garcia', 'IT', 75000, '2020-11-22'), ('James', 'Martinez', 'Marketing', 60000, '2021-03-18'), ('Olivia...
Read more

How to find all the customers who placed orders on three consecutive days | SQL Scenario questions

  DML Script: DROP TABLE IF EXISTS Orders CREATE TABLE Orders ( customer_name VARCHAR(255), order_date DATETIME ); INSERT INTO Orders (customer_name, order_date) VALUES ('Alice', '2024-04-01'); INSERT INTO Orders (customer_name, order_date) VALUES ('Bob', '2024-04-01'); INSERT INTO Orders (customer_name, order_date) VALUES ('Alice', '2024-04-02'); INSERT INTO Orders (customer_name, order_date) VALUES ('Bob', '2024-04-02'); INSERT INTO Orders (customer_name, order_date) VALUES ('Charlie', '2024-04-03'); INSERT INTO Orders (customer_name, order_date) VALUES ('Alice', '2024-04-03'); INSERT INTO Orders (customer_name, order_date) VALUES ('Alice', '2024-04-04'); INSERT INTO Orders (customer_name, order_date) VALUES ('Bob', '2024-04-04'); INSERT INTO Orders (customer_name, order_date) VALUES ('Charlie', '2024-04-05'); INSER...
Read more

ACCENTURE SQL INTERVIEW QUESTION | Change the ProductIDs

 DROP TABLE IF EXISTS Products; CREATE TABLE Products (     ProductID INT PRIMARY KEY,     Product VARCHAR(255),     Category VARCHAR(100) ); INSERT INTO Products (ProductID, Product, Category) VALUES     (1, 'Laptop', 'Electronics'),     (2, 'Smartphone', 'Electronics'),     (3, 'Tablet', 'Electronics'),     (4, 'Headphones', 'Accessories'),     (5, 'Smartwatch', 'Accessories'),     (6, 'Keyboard', 'Accessories'),     (7, 'Mouse', 'Accessories'),     (8, 'Monitor', 'Accessories'),     (9, 'Printer', 'Electronics');
Read more